# Line slope calculator x-9y=-18

**Straight line given by points A[0; 2] and B[9; 3]**

## Calculation:

**Slope-intercept form of line:**y = 0.1111x+2

**Canonical form of the line equation:**x-9y+18 = 0

**Parametric form of the line equation:**

x = 9t

y = t+2 ; t ∈ R

**Slope:**m = 0.1111

**Slope angle of line: φ =**6°20'25″ = 0.1107 rad

**X intercept:**x

_{0}= -18

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.9878

**The length of the segment AB: |AB| =**9.0554

**Vector: AB =**(9; 1)

**Normal vector: n =**(1; -9)

**Midpoint of the segment AB: M =**[4.5; 2.5]

**Perpendicular Bisector equation:**9x+y-43 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (9; 3) ; |OB| = 9.4868**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 71°33'54″ = 1.249 rad**